Search a number
-
+
530533131432541 is a prime number
BaseRepresentation
bin111100010100001000101111…
…0110101110011001001011101
32120120110110202010010021102021
41320220101132311303021131
51024014223323121320131
65120203320025500141
7216514516400063326
oct17050213665631135
92516413663107367
10530533131432541
111440539237a5a26
124b604a60341651
1319a050a0cc7b53
149501d24cd144d
1541505b6cdae11
hex1e2845ed7325d

530533131432541 has 2 divisors, whose sum is σ = 530533131432542. Its totient is φ = 530533131432540.

The previous prime is 530533131432431. The next prime is 530533131432569. The reversal of 530533131432541 is 145234131335035.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 398435692409316 + 132097439023225 = 19960854^2 + 11493365^2 .

It is a cyclic number.

It is not a de Polignac number, because 530533131432541 - 27 = 530533131432413 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (530533131432571) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265266565716270 + 265266565716271.

It is an arithmetic number, because the mean of its divisors is an integer number (265266565716271).

Almost surely, 2530533131432541 is an apocalyptic number.

It is an amenable number.

530533131432541 is a deficient number, since it is larger than the sum of its proper divisors (1).

530533131432541 is an equidigital number, since it uses as much as digits as its factorization.

530533131432541 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 972000, while the sum is 43.

Adding to 530533131432541 its reverse (145234131335035), we get a palindrome (675767262767576).

The spelling of 530533131432541 in words is "five hundred thirty trillion, five hundred thirty-three billion, one hundred thirty-one million, four hundred thirty-two thousand, five hundred forty-one".