Base | Representation |
---|---|
bin | 110001011010001111… |
… | …000110000111011111 |
3 | 12001221101112202122122 |
4 | 301122033012013133 |
5 | 1332123144423312 |
6 | 40212240533155 |
7 | 3555500300351 |
oct | 613217060737 |
9 | 161841482578 |
10 | 53053514207 |
11 | 20555364511 |
12 | a3476211bb |
13 | 5006570075 |
14 | 27d40a70d1 |
15 | 15a79a9b72 |
hex | c5a3c61df |
53053514207 has 2 divisors, whose sum is σ = 53053514208. Its totient is φ = 53053514206.
The previous prime is 53053514149. The next prime is 53053514233. The reversal of 53053514207 is 70241535035.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 53053514207 - 28 = 53053513951 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53053514257) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26526757103 + 26526757104.
It is an arithmetic number, because the mean of its divisors is an integer number (26526757104).
Almost surely, 253053514207 is an apocalyptic number.
53053514207 is a deficient number, since it is larger than the sum of its proper divisors (1).
53053514207 is an equidigital number, since it uses as much as digits as its factorization.
53053514207 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 63000, while the sum is 35.
The spelling of 53053514207 in words is "fifty-three billion, fifty-three million, five hundred fourteen thousand, two hundred seven".
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