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53054011 is a prime number
BaseRepresentation
bin1100101001100…
…0101000111011
310200211102102101
43022120220323
5102040212021
65133044231
71212644263
oct312305073
9120742371
1053054011
1127a4729a
1215926677
13acb750a
1470907a3
1549cea91
hex3298a3b

53054011 has 2 divisors, whose sum is σ = 53054012. Its totient is φ = 53054010.

The previous prime is 53054009. The next prime is 53054069. The reversal of 53054011 is 11045035.

53054011 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 53054011 - 21 = 53054009 is a prime.

Together with 53054009, it forms a pair of twin primes.

It is a self number, because there is not a number n which added to its sum of digits gives 53054011.

It is not a weakly prime, because it can be changed into another prime (53054081) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26527005 + 26527006.

It is an arithmetic number, because the mean of its divisors is an integer number (26527006).

Almost surely, 253054011 is an apocalyptic number.

53054011 is a deficient number, since it is larger than the sum of its proper divisors (1).

53054011 is an equidigital number, since it uses as much as digits as its factorization.

53054011 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 300, while the sum is 19.

The square root of 53054011 is about 7283.8184354087. The cubic root of 53054011 is about 375.7561300585.

Adding to 53054011 its reverse (11045035), we get a palindrome (64099046).

It can be divided in two parts, 5305 and 4011, that added together give a triangular number (9316 = T136).

The spelling of 53054011 in words is "fifty-three million, fifty-four thousand, eleven".