Base | Representation |
---|---|
bin | 100110100110100001010… |
… | …1010110010101000011101 |
3 | 200210012011122222022020101 |
4 | 1031031002222302220131 |
5 | 1143410431144434003 |
6 | 15141134001221101 |
7 | 1055205556325401 |
oct | 115150252625035 |
9 | 20705148868211 |
10 | 5305403124253 |
11 | 1766010830001 |
12 | 718280931791 |
13 | 2c63b34180cb |
14 | 144ad6325101 |
15 | 9301441611d |
hex | 4d342ab2a1d |
5305403124253 has 2 divisors, whose sum is σ = 5305403124254. Its totient is φ = 5305403124252.
The previous prime is 5305403124191. The next prime is 5305403124299. The reversal of 5305403124253 is 3524213045035.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3874704854329 + 1430698269924 = 1968427^2 + 1196118^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5305403124253 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5305403124653) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2652701562126 + 2652701562127.
It is an arithmetic number, because the mean of its divisors is an integer number (2652701562127).
Almost surely, 25305403124253 is an apocalyptic number.
It is an amenable number.
5305403124253 is a deficient number, since it is larger than the sum of its proper divisors (1).
5305403124253 is an equidigital number, since it uses as much as digits as its factorization.
5305403124253 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216000, while the sum is 37.
Adding to 5305403124253 its reverse (3524213045035), we get a palindrome (8829616169288).
The spelling of 5305403124253 in words is "five trillion, three hundred five billion, four hundred three million, one hundred twenty-four thousand, two hundred fifty-three".
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