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53054437 is a prime number
BaseRepresentation
bin1100101001100…
…0101111100101
310200211110000011
43022120233211
5102040220222
65133050221
71212645442
oct312305745
9120743004
1053054437
1127a47647
1215926971
13acb7777
1470909c9
1549cec77
hex3298be5

53054437 has 2 divisors, whose sum is σ = 53054438. Its totient is φ = 53054436.

The previous prime is 53054383. The next prime is 53054453. The reversal of 53054437 is 73445035.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 47527236 + 5527201 = 6894^2 + 2351^2 .

It is a cyclic number.

It is not a de Polignac number, because 53054437 - 215 = 53021669 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 53054399 and 53054408.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (53051437) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26527218 + 26527219.

It is an arithmetic number, because the mean of its divisors is an integer number (26527219).

Almost surely, 253054437 is an apocalyptic number.

It is an amenable number.

53054437 is a deficient number, since it is larger than the sum of its proper divisors (1).

53054437 is an equidigital number, since it uses as much as digits as its factorization.

53054437 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 25200, while the sum is 31.

The square root of 53054437 is about 7283.8476782536. The cubic root of 53054437 is about 375.7571357738.

The spelling of 53054437 in words is "fifty-three million, fifty-four thousand, four hundred thirty-seven".