Base | Representation |
---|---|
bin | 111100010100010001000111… |
… | …0101001001110110110100111 |
3 | 2120120112012011022012111001212 |
4 | 1320220202032221032312213 |
5 | 1024020022140002014303 |
6 | 5120215452223542035 |
7 | 216516024115412666 |
oct | 17050421651166647 |
9 | 2516465138174055 |
10 | 530551113313703 |
11 | 144060511032439 |
12 | 4b60843a45a91b |
13 | 19a069a8553311 |
14 | 9502b4d162ddd |
15 | 4150cba7b5ad8 |
hex | 1e2888ea4eda7 |
530551113313703 has 2 divisors, whose sum is σ = 530551113313704. Its totient is φ = 530551113313702.
The previous prime is 530551113313681. The next prime is 530551113313709. The reversal of 530551113313703 is 307313311155035.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 530551113313703 - 232 = 530546818346407 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (530551113313709) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265275556656851 + 265275556656852.
It is an arithmetic number, because the mean of its divisors is an integer number (265275556656852).
Almost surely, 2530551113313703 is an apocalyptic number.
530551113313703 is a deficient number, since it is larger than the sum of its proper divisors (1).
530551113313703 is an equidigital number, since it uses as much as digits as its factorization.
530551113313703 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 212625, while the sum is 41.
Adding to 530551113313703 its reverse (307313311155035), we get a palindrome (837864424468738).
The spelling of 530551113313703 in words is "five hundred thirty trillion, five hundred fifty-one billion, one hundred thirteen million, three hundred thirteen thousand, seven hundred three".
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