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530552315437 is a prime number
BaseRepresentation
bin1111011100001110110…
…00011101111000101101
31212201110002210010221221
413232013120131320231
532143032343043222
61043422105223341
753221403162314
oct7560730357055
91781402703857
10530552315437
11195007a50271
12869a8a91b51
133b052a84231
141b970b6127b
15dc02eab0c7
hex7b8761de2d

530552315437 has 2 divisors, whose sum is σ = 530552315438. Its totient is φ = 530552315436.

The previous prime is 530552315413. The next prime is 530552315467. The reversal of 530552315437 is 734513255035.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 524018179881 + 6534135556 = 723891^2 + 80834^2 .

It is a cyclic number.

It is not a de Polignac number, because 530552315437 - 27 = 530552315309 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 530552315393 and 530552315402.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (530552315467) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265276157718 + 265276157719.

It is an arithmetic number, because the mean of its divisors is an integer number (265276157719).

Almost surely, 2530552315437 is an apocalyptic number.

It is an amenable number.

530552315437 is a deficient number, since it is larger than the sum of its proper divisors (1).

530552315437 is an equidigital number, since it uses as much as digits as its factorization.

530552315437 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 945000, while the sum is 43.

The spelling of 530552315437 in words is "five hundred thirty billion, five hundred fifty-two million, three hundred fifteen thousand, four hundred thirty-seven".