Base | Representation |
---|---|
bin | 111100010100101011111001… |
… | …1100010111100000101011111 |
3 | 2120120201200122111012102002112 |
4 | 1320221113303202330011133 |
5 | 1024021442444012101011 |
6 | 5120302124444144235 |
7 | 216523131522431051 |
oct | 17051276342740537 |
9 | 2516650574172075 |
10 | 530608640737631 |
11 | 1440829518374a5 |
12 | 4b61761423807b |
13 | 19a0c245963631 |
14 | 95058494a38d1 |
15 | 4152535e0858b |
hex | 1e295f38bc15f |
530608640737631 has 2 divisors, whose sum is σ = 530608640737632. Its totient is φ = 530608640737630.
The previous prime is 530608640737621. The next prime is 530608640737729. The reversal of 530608640737631 is 136737046806035.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 530608640737631 - 246 = 460239896559967 is a prime.
It is a super-2 number, since 2×5306086407376312 (a number of 30 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (530608640737621) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265304320368815 + 265304320368816.
It is an arithmetic number, because the mean of its divisors is an integer number (265304320368816).
Almost surely, 2530608640737631 is an apocalyptic number.
530608640737631 is a deficient number, since it is larger than the sum of its proper divisors (1).
530608640737631 is an equidigital number, since it uses as much as digits as its factorization.
530608640737631 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 45722880, while the sum is 59.
The spelling of 530608640737631 in words is "five hundred thirty trillion, six hundred eight billion, six hundred forty million, seven hundred thirty-seven thousand, six hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.068 sec. • engine limits •