Base | Representation |
---|---|
bin | 11000001000010100011101… |
… | …10001111111111010011111 |
3 | 20221212201101101101120012121 |
4 | 30010022032301333322133 |
5 | 23423333314342240203 |
6 | 304504312341043411 |
7 | 14114430161261143 |
oct | 1404121661777237 |
9 | 227781341346177 |
10 | 53062421446303 |
11 | 159a8712632315 |
12 | 5b4ba296b6567 |
13 | 237b9c3567509 |
14 | d163407d7223 |
15 | 62041e4b70bd |
hex | 30428ec7fe9f |
53062421446303 has 2 divisors, whose sum is σ = 53062421446304. Its totient is φ = 53062421446302.
The previous prime is 53062421446297. The next prime is 53062421446343. The reversal of 53062421446303 is 30364412426035.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 53062421446303 - 217 = 53062421315231 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 53062421446303.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53062421446343) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26531210723151 + 26531210723152.
It is an arithmetic number, because the mean of its divisors is an integer number (26531210723152).
Almost surely, 253062421446303 is an apocalyptic number.
53062421446303 is a deficient number, since it is larger than the sum of its proper divisors (1).
53062421446303 is an equidigital number, since it uses as much as digits as its factorization.
53062421446303 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1244160, while the sum is 43.
The spelling of 53062421446303 in words is "fifty-three trillion, sixty-two billion, four hundred twenty-one million, four hundred forty-six thousand, three hundred three".
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