Base | Representation |
---|---|
bin | 100110100111000101000… |
… | …1111111100000001011101 |
3 | 200210022021100201100221122 |
4 | 1031032022033330001131 |
5 | 1143420411113410011 |
6 | 15141453101140325 |
7 | 1055250411065303 |
oct | 115161217740135 |
9 | 20708240640848 |
10 | 5306604044381 |
11 | 1766577705082 |
12 | 718556b5a6a5 |
13 | 2c6545172333 |
14 | 144baba14273 |
15 | 93084a843db |
hex | 4d38a3fc05d |
5306604044381 has 2 divisors, whose sum is σ = 5306604044382. Its totient is φ = 5306604044380.
The previous prime is 5306604044249. The next prime is 5306604044387. The reversal of 5306604044381 is 1834404066035.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 5103234613156 + 203369431225 = 2259034^2 + 450965^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5306604044381 is a prime.
It is a super-2 number, since 2×53066040443812 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5306604044387) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2653302022190 + 2653302022191.
It is an arithmetic number, because the mean of its divisors is an integer number (2653302022191).
Almost surely, 25306604044381 is an apocalyptic number.
It is an amenable number.
5306604044381 is a deficient number, since it is larger than the sum of its proper divisors (1).
5306604044381 is an equidigital number, since it uses as much as digits as its factorization.
5306604044381 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 829440, while the sum is 44.
The spelling of 5306604044381 in words is "five trillion, three hundred six billion, six hundred four million, forty-four thousand, three hundred eighty-one".
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