Base | Representation |
---|---|
bin | 11000001000011100100100… |
… | …01011101011010100011101 |
3 | 20221220010121200111121111021 |
4 | 30010032102023223110131 |
5 | 23423421223002223022 |
6 | 304510312244124141 |
7 | 14114643055026214 |
oct | 1404162213532435 |
9 | 227803550447437 |
10 | 53066773476637 |
11 | 159aa5461a80a8 |
12 | 5b50843096651 |
13 | 237c2380a32ab |
14 | d166347c607b |
15 | 6205c65c77c7 |
hex | 3043922eb51d |
53066773476637 has 2 divisors, whose sum is σ = 53066773476638. Its totient is φ = 53066773476636.
The previous prime is 53066773476599. The next prime is 53066773476727. The reversal of 53066773476637 is 73667437766035.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 47314119932676 + 5752653543961 = 6878526^2 + 2398469^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-53066773476637 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53066773470637) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26533386738318 + 26533386738319.
It is an arithmetic number, because the mean of its divisors is an integer number (26533386738319).
Almost surely, 253066773476637 is an apocalyptic number.
It is an amenable number.
53066773476637 is a deficient number, since it is larger than the sum of its proper divisors (1).
53066773476637 is an equidigital number, since it uses as much as digits as its factorization.
53066773476637 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1680315840, while the sum is 70.
The spelling of 53066773476637 in words is "fifty-three trillion, sixty-six billion, seven hundred seventy-three million, four hundred seventy-six thousand, six hundred thirty-seven".
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