Base | Representation |
---|---|
bin | 11111101000010… |
… | …111010010000001 |
3 | 1100222120001222212 |
4 | 133220113102001 |
5 | 2041323043232 |
6 | 124354111505 |
7 | 16102442621 |
oct | 3750272201 |
9 | 1328501885 |
10 | 530674817 |
11 | 252608932 |
12 | 12987b595 |
13 | 85c3528a |
14 | 5069c881 |
15 | 318c6eb2 |
hex | 1fa17481 |
530674817 has 2 divisors, whose sum is σ = 530674818. Its totient is φ = 530674816.
The previous prime is 530674811. The next prime is 530674819. The reversal of 530674817 is 718476035.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 354342976 + 176331841 = 18824^2 + 13279^2 .
It is a cyclic number.
It is not a de Polignac number, because 530674817 - 214 = 530658433 is a prime.
It is a super-2 number, since 2×5306748172 = 563231522795966978, which contains 22 as substring.
Together with 530674819, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (530674811) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265337408 + 265337409.
It is an arithmetic number, because the mean of its divisors is an integer number (265337409).
Almost surely, 2530674817 is an apocalyptic number.
It is an amenable number.
530674817 is a deficient number, since it is larger than the sum of its proper divisors (1).
530674817 is an equidigital number, since it uses as much as digits as its factorization.
530674817 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 141120, while the sum is 41.
The square root of 530674817 is about 23036.3802929193. The cubic root of 530674817 is about 809.6105514915.
The spelling of 530674817 in words is "five hundred thirty million, six hundred seventy-four thousand, eight hundred seventeen".
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