Base | Representation |
---|---|
bin | 11111101000011… |
… | …001010100001011 |
3 | 1100222120111102101 |
4 | 133220121110023 |
5 | 2041323330042 |
6 | 124354214231 |
7 | 16102506121 |
oct | 3750312413 |
9 | 1328514371 |
10 | 530683147 |
11 | 252614115 |
12 | 129884377 |
13 | 85c38cc7 |
14 | 506a1911 |
15 | 318c96b7 |
hex | 1fa1950b |
530683147 has 2 divisors, whose sum is σ = 530683148. Its totient is φ = 530683146.
The previous prime is 530683123. The next prime is 530683171. The reversal of 530683147 is 741386035.
It is a balanced prime because it is at equal distance from previous prime (530683123) and next prime (530683171).
It is a cyclic number.
It is not a de Polignac number, because 530683147 - 219 = 530158859 is a prime.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (530680147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265341573 + 265341574.
It is an arithmetic number, because the mean of its divisors is an integer number (265341574).
Almost surely, 2530683147 is an apocalyptic number.
530683147 is a deficient number, since it is larger than the sum of its proper divisors (1).
530683147 is an equidigital number, since it uses as much as digits as its factorization.
530683147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 60480, while the sum is 37.
The square root of 530683147 is about 23036.5610931840. The cubic root of 530683147 is about 809.6147876202.
The spelling of 530683147 in words is "five hundred thirty million, six hundred eighty-three thousand, one hundred forty-seven".
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