Base | Representation |
---|---|
bin | 1111011100100000111… |
… | …11011001000101101011 |
3 | 1212201211202022201021202 |
4 | 13232100133121011223 |
5 | 32143341003010424 |
6 | 1043445204354415 |
7 | 53225240065355 |
oct | 7562037310553 |
9 | 1781752281252 |
10 | 530705125739 |
11 | 195086231978 |
12 | 86a300a5a0b |
13 | 3b078628329 |
14 | 1b98717c0d5 |
15 | dc115e32ae |
hex | 7b907d916b |
530705125739 has 2 divisors, whose sum is σ = 530705125740. Its totient is φ = 530705125738.
The previous prime is 530705125669. The next prime is 530705125777. The reversal of 530705125739 is 937521507035.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 530705125739 - 224 = 530688348523 is a prime.
It is a super-2 number, since 2×5307051257392 (a number of 24 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is a junction number, because it is equal to n+sod(n) for n = 530705125693 and 530705125702.
It is not a weakly prime, because it can be changed into another prime (530705125789) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265352562869 + 265352562870.
It is an arithmetic number, because the mean of its divisors is an integer number (265352562870).
Almost surely, 2530705125739 is an apocalyptic number.
530705125739 is a deficient number, since it is larger than the sum of its proper divisors (1).
530705125739 is an equidigital number, since it uses as much as digits as its factorization.
530705125739 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 992250, while the sum is 47.
The spelling of 530705125739 in words is "five hundred thirty billion, seven hundred five million, one hundred twenty-five thousand, seven hundred thirty-nine".
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