Base | Representation |
---|---|
bin | 1001111000101001… |
… | …10011001000010111 |
3 | 111200212011012111111 |
4 | 10330110303020113 |
5 | 41332101140232 |
6 | 2234340315451 |
7 | 245341126315 |
oct | 47424631027 |
9 | 14625135444 |
10 | 5307052567 |
11 | 2283769163 |
12 | 10413a2b87 |
13 | 6676587bb |
14 | 384b8d0b5 |
15 | 210daa047 |
hex | 13c533217 |
5307052567 has 2 divisors, whose sum is σ = 5307052568. Its totient is φ = 5307052566.
The previous prime is 5307052559. The next prime is 5307052589. The reversal of 5307052567 is 7652507035.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5307052567 - 23 = 5307052559 is a prime.
It is a super-3 number, since 3×53070525673 (a number of 30 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5307052067) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2653526283 + 2653526284.
It is an arithmetic number, because the mean of its divisors is an integer number (2653526284).
Almost surely, 25307052567 is an apocalyptic number.
5307052567 is a deficient number, since it is larger than the sum of its proper divisors (1).
5307052567 is an equidigital number, since it uses as much as digits as its factorization.
5307052567 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 220500, while the sum is 40.
The square root of 5307052567 is about 72849.5200190090. The cubic root of 5307052567 is about 1744.2864072408.
The spelling of 5307052567 in words is "five billion, three hundred seven million, fifty-two thousand, five hundred sixty-seven".
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