Base | Representation |
---|---|
bin | 1001111000101010… |
… | …01110101001110011 |
3 | 111200212100221010202 |
4 | 10330111032221303 |
5 | 41332113242144 |
6 | 2234342545415 |
7 | 245342106062 |
oct | 47425165163 |
9 | 14625327122 |
10 | 5307165299 |
11 | 2283835927 |
12 | 104143826b |
13 | 667697bc7 |
14 | 384bbc1d9 |
15 | 210dcd64e |
hex | 13c54ea73 |
5307165299 has 2 divisors, whose sum is σ = 5307165300. Its totient is φ = 5307165298.
The previous prime is 5307165289. The next prime is 5307165313. The reversal of 5307165299 is 9925617035.
5307165299 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5307165299 is a prime.
It is a super-3 number, since 3×53071652993 (a number of 30 digits) contains 333 as substring.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (5307165289) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2653582649 + 2653582650.
It is an arithmetic number, because the mean of its divisors is an integer number (2653582650).
Almost surely, 25307165299 is an apocalyptic number.
5307165299 is a deficient number, since it is larger than the sum of its proper divisors (1).
5307165299 is an equidigital number, since it uses as much as digits as its factorization.
5307165299 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 510300, while the sum is 47.
The square root of 5307165299 is about 72850.2937468340. The cubic root of 5307165299 is about 1744.2987578189.
The spelling of 5307165299 in words is "five billion, three hundred seven million, one hundred sixty-five thousand, two hundred ninety-nine".
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