Base | Representation |
---|---|
bin | 11000001000110000101010… |
… | …01000111010110000100101 |
3 | 20221221011110110012100021112 |
4 | 30010120111020322300211 |
5 | 23424110320442101313 |
6 | 304515254503354405 |
7 | 14115504300162512 |
oct | 1404302510726045 |
9 | 227834413170245 |
10 | 53077560503333 |
11 | 15a040811a19a3 |
12 | 5b52953752a05 |
13 | 2380266b50622 |
14 | d16d79298309 |
15 | 620a085e88a8 |
hex | 30461523ac25 |
53077560503333 has 2 divisors, whose sum is σ = 53077560503334. Its totient is φ = 53077560503332.
The previous prime is 53077560503251. The next prime is 53077560503339. The reversal of 53077560503333 is 33330506577035.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 28584345823489 + 24493214679844 = 5346433^2 + 4949062^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-53077560503333 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53077560503339) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26538780251666 + 26538780251667.
It is an arithmetic number, because the mean of its divisors is an integer number (26538780251667).
Almost surely, 253077560503333 is an apocalyptic number.
It is an amenable number.
53077560503333 is a deficient number, since it is larger than the sum of its proper divisors (1).
53077560503333 is an equidigital number, since it uses as much as digits as its factorization.
53077560503333 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8930250, while the sum is 50.
The spelling of 53077560503333 in words is "fifty-three trillion, seventy-seven billion, five hundred sixty million, five hundred three thousand, three hundred thirty-three".
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