Base | Representation |
---|---|
bin | 110001011011101101… |
… | …001101000110110101 |
3 | 12002000002222010202111 |
4 | 301123231031012311 |
5 | 1332201003344443 |
6 | 40214521411021 |
7 | 3556220060134 |
oct | 613355150665 |
9 | 162002863674 |
10 | 53078184373 |
11 | 20568284585 |
12 | a353939a71 |
13 | 500b6ca0b6 |
14 | 27d748991b |
15 | 15a9c2e69d |
hex | c5bb4d1b5 |
53078184373 has 2 divisors, whose sum is σ = 53078184374. Its totient is φ = 53078184372.
The previous prime is 53078184359. The next prime is 53078184377. The reversal of 53078184373 is 37348187035.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 48682892164 + 4395292209 = 220642^2 + 66297^2 .
It is a cyclic number.
It is not a de Polignac number, because 53078184373 - 29 = 53078183861 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53078184377) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26539092186 + 26539092187.
It is an arithmetic number, because the mean of its divisors is an integer number (26539092187).
Almost surely, 253078184373 is an apocalyptic number.
It is an amenable number.
53078184373 is a deficient number, since it is larger than the sum of its proper divisors (1).
53078184373 is an equidigital number, since it uses as much as digits as its factorization.
53078184373 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1693440, while the sum is 49.
The spelling of 53078184373 in words is "fifty-three billion, seventy-eight million, one hundred eighty-four thousand, three hundred seventy-three".
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