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53084113 is a prime number
BaseRepresentation
bin1100101001111…
…1111111010001
310200212221201021
43022133333101
5102042142423
65133435441
71213131115
oct312377721
9120787637
1053084113
1127a67975
121593bb81
13acc8124
14709b745
1549d895d
hex329ffd1

53084113 has 2 divisors, whose sum is σ = 53084114. Its totient is φ = 53084112.

The previous prime is 53084099. The next prime is 53084117. The reversal of 53084113 is 31148035.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 49112064 + 3972049 = 7008^2 + 1993^2 .

It is a cyclic number.

It is not a de Polignac number, because 53084113 - 217 = 52953041 is a prime.

It is not a weakly prime, because it can be changed into another prime (53084117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26542056 + 26542057.

It is an arithmetic number, because the mean of its divisors is an integer number (26542057).

Almost surely, 253084113 is an apocalyptic number.

It is an amenable number.

53084113 is a deficient number, since it is larger than the sum of its proper divisors (1).

53084113 is an equidigital number, since it uses as much as digits as its factorization.

53084113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1440, while the sum is 25.

The square root of 53084113 is about 7285.8845036138. The cubic root of 53084113 is about 375.8271826347.

The spelling of 53084113 in words is "fifty-three million, eighty-four thousand, one hundred thirteen".