Base | Representation |
---|---|
bin | 100110101000101010101… |
… | …0101100110110001100111 |
3 | 200210122001211002010220201 |
4 | 1031101111111212301213 |
5 | 1143444400343230223 |
6 | 15143215134411331 |
7 | 1055431013243023 |
oct | 115212525466147 |
9 | 20718054063821 |
10 | 5310011305063 |
11 | 1767a65a4a4a3 |
12 | 719148060b47 |
13 | 2c696903ac0a |
14 | 145012351383 |
15 | 931d3c72ead |
hex | 4d455566c67 |
5310011305063 has 2 divisors, whose sum is σ = 5310011305064. Its totient is φ = 5310011305062.
The previous prime is 5310011305051. The next prime is 5310011305141. The reversal of 5310011305063 is 3605031100135.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5310011305063 - 229 = 5309474434151 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5310011305163) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2655005652531 + 2655005652532.
It is an arithmetic number, because the mean of its divisors is an integer number (2655005652532).
Almost surely, 25310011305063 is an apocalyptic number.
5310011305063 is a deficient number, since it is larger than the sum of its proper divisors (1).
5310011305063 is an equidigital number, since it uses as much as digits as its factorization.
5310011305063 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4050, while the sum is 28.
Adding to 5310011305063 its reverse (3605031100135), we get a palindrome (8915042405198).
The spelling of 5310011305063 in words is "five trillion, three hundred ten billion, eleven million, three hundred five thousand, sixty-three".
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