Base | Representation |
---|---|
bin | 111100010111100011101001… |
… | …1001010100000101110010101 |
3 | 2120122010102011101220010201212 |
4 | 1320233013103022200232111 |
5 | 1024044424111010020141 |
6 | 5121203303541031205 |
7 | 216563501106613331 |
oct | 17057072312405625 |
9 | 2518112141803655 |
10 | 531003234454421 |
11 | 144215230695243 |
12 | 4b67bb989b5505 |
13 | 19a3a50c211911 |
14 | 951a99d6467c1 |
15 | 415c92cd952eb |
hex | 1e2f1d32a0b95 |
531003234454421 has 2 divisors, whose sum is σ = 531003234454422. Its totient is φ = 531003234454420.
The previous prime is 531003234454417. The next prime is 531003234454457. The reversal of 531003234454421 is 124454432300135.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 530360173202500 + 643061251921 = 23029550^2 + 801911^2 .
It is a cyclic number.
It is not a de Polignac number, because 531003234454421 - 22 = 531003234454417 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (531003234454411) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265501617227210 + 265501617227211.
It is an arithmetic number, because the mean of its divisors is an integer number (265501617227211).
Almost surely, 2531003234454421 is an apocalyptic number.
It is an amenable number.
531003234454421 is a deficient number, since it is larger than the sum of its proper divisors (1).
531003234454421 is an equidigital number, since it uses as much as digits as its factorization.
531003234454421 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 691200, while the sum is 41.
Adding to 531003234454421 its reverse (124454432300135), we get a palindrome (655457666754556).
The spelling of 531003234454421 in words is "five hundred thirty-one trillion, three billion, two hundred thirty-four million, four hundred fifty-four thousand, four hundred twenty-one".
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