Base | Representation |
---|---|
bin | 110001011101000101… |
… | …011100010000011111 |
3 | 12002001201111022011012 |
4 | 301131011130100133 |
5 | 1332222414040403 |
6 | 40221105245435 |
7 | 3556620505514 |
oct | 613505342037 |
9 | 162051438135 |
10 | 53101315103 |
11 | 2057a342a91 |
12 | a35b63387b |
13 | 5013438515 |
14 | 27da58b30b |
15 | 15abc9ced8 |
hex | c5d15c41f |
53101315103 has 2 divisors, whose sum is σ = 53101315104. Its totient is φ = 53101315102.
The previous prime is 53101315097. The next prime is 53101315117. The reversal of 53101315103 is 30151310135.
53101315103 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-53101315103 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53101315133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26550657551 + 26550657552.
It is an arithmetic number, because the mean of its divisors is an integer number (26550657552).
Almost surely, 253101315103 is an apocalyptic number.
53101315103 is a deficient number, since it is larger than the sum of its proper divisors (1).
53101315103 is an equidigital number, since it uses as much as digits as its factorization.
53101315103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 675, while the sum is 23.
Adding to 53101315103 its reverse (30151310135), we get a palindrome (83252625238).
The spelling of 53101315103 in words is "fifty-three billion, one hundred one million, three hundred fifteen thousand, one hundred three".
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