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53101366649141 is a prime number
BaseRepresentation
bin11000001001011101000000…
…00110001010000100110101
320222000102220112122212000112
430010232200012022010311
523430003044330233031
6304534233035552405
714120306240113436
oct1404564006120465
9228012815585015
1053101366649141
1115a1318813a668
125b574982bb705
13238258bc34b35
14d18196c7148d
1562144d59662b
hex304ba018a135

53101366649141 has 2 divisors, whose sum is σ = 53101366649142. Its totient is φ = 53101366649140.

The previous prime is 53101366649087. The next prime is 53101366649161. The reversal of 53101366649141 is 14194666310135.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 40525052033041 + 12576314616100 = 6365929^2 + 3546310^2 .

It is a cyclic number.

It is not a de Polignac number, because 53101366649141 - 218 = 53101366386997 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 53101366649141.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (53101366649161) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26550683324570 + 26550683324571.

It is an arithmetic number, because the mean of its divisors is an integer number (26550683324571).

Almost surely, 253101366649141 is an apocalyptic number.

It is an amenable number.

53101366649141 is a deficient number, since it is larger than the sum of its proper divisors (1).

53101366649141 is an equidigital number, since it uses as much as digits as its factorization.

53101366649141 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1399680, while the sum is 50.

The spelling of 53101366649141 in words is "fifty-three trillion, one hundred one billion, three hundred sixty-six million, six hundred forty-nine thousand, one hundred forty-one".