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531024113042149 is a prime number
BaseRepresentation
bin111100010111101101010111…
…1101000000000001011100101
32120122012102001110122021202211
41320233122233220000023211
51024100244340414322044
65121221035413403421
7216565140360645436
oct17057325750001345
92518172043567684
10531024113042149
11144223075051221
124b684045039571
1319a3c488926a3c
14951b9c04b348d
15415d250d0d634
hex1e2f6afa002e5

531024113042149 has 2 divisors, whose sum is σ = 531024113042150. Its totient is φ = 531024113042148.

The previous prime is 531024113042083. The next prime is 531024113042167. The reversal of 531024113042149 is 941240311420135.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 408783294192100 + 122240818850049 = 20218390^2 + 11056257^2 .

It is a cyclic number.

It is not a de Polignac number, because 531024113042149 - 27 = 531024113042021 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (531024113040149) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265512056521074 + 265512056521075.

It is an arithmetic number, because the mean of its divisors is an integer number (265512056521075).

Almost surely, 2531024113042149 is an apocalyptic number.

It is an amenable number.

531024113042149 is a deficient number, since it is larger than the sum of its proper divisors (1).

531024113042149 is an equidigital number, since it uses as much as digits as its factorization.

531024113042149 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 103680, while the sum is 40.

The spelling of 531024113042149 in words is "five hundred thirty-one trillion, twenty-four billion, one hundred thirteen million, forty-two thousand, one hundred forty-nine".