Base | Representation |
---|---|
bin | 110001011101010000… |
… | …001001111010010001 |
3 | 12002001220202222121021 |
4 | 301131100021322101 |
5 | 1332224123423122 |
6 | 40221245355441 |
7 | 3556653413413 |
oct | 613520117221 |
9 | 162056688537 |
10 | 53104123537 |
11 | 20580991003 |
12 | a360568b81 |
13 | 5013bac90a |
14 | 27daabc9b3 |
15 | 15ac1551c7 |
hex | c5d409e91 |
53104123537 has 2 divisors, whose sum is σ = 53104123538. Its totient is φ = 53104123536.
The previous prime is 53104123529. The next prime is 53104123573. The reversal of 53104123537 is 73532140135.
Together with next prime (53104123573) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 52192143936 + 911979601 = 228456^2 + 30199^2 .
It is a cyclic number.
It is not a de Polignac number, because 53104123537 - 23 = 53104123529 is a prime.
It is not a weakly prime, because it can be changed into another prime (53104123577) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26552061768 + 26552061769.
It is an arithmetic number, because the mean of its divisors is an integer number (26552061769).
Almost surely, 253104123537 is an apocalyptic number.
It is an amenable number.
53104123537 is a deficient number, since it is larger than the sum of its proper divisors (1).
53104123537 is an equidigital number, since it uses as much as digits as its factorization.
53104123537 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 37800, while the sum is 34.
The spelling of 53104123537 in words is "fifty-three billion, one hundred four million, one hundred twenty-three thousand, five hundred thirty-seven".
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