Base | Representation |
---|---|
bin | 111100010111110101110000… |
… | …0101000111001101001111011 |
3 | 2120122021010112001221012102021 |
4 | 1320233223200220321221323 |
5 | 1024101043222444332311 |
6 | 5121233214015015311 |
7 | 216566345444013205 |
oct | 17057534050715173 |
9 | 2518233461835367 |
10 | 531042115230331 |
11 | 14422a7728986a1 |
12 | 4b687629b0a537 |
13 | 19a410974422b3 |
14 | 951c80b30d775 |
15 | 415d95649a171 |
hex | 1e2fae0a39a7b |
531042115230331 has 2 divisors, whose sum is σ = 531042115230332. Its totient is φ = 531042115230330.
The previous prime is 531042115230113. The next prime is 531042115230349. The reversal of 531042115230331 is 133032511240135.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 531042115230331 - 221 = 531042113133179 is a prime.
It is a super-2 number, since 2×5310421152303312 (a number of 30 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (531042115236331) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265521057615165 + 265521057615166.
It is an arithmetic number, because the mean of its divisors is an integer number (265521057615166).
Almost surely, 2531042115230331 is an apocalyptic number.
531042115230331 is a deficient number, since it is larger than the sum of its proper divisors (1).
531042115230331 is an equidigital number, since it uses as much as digits as its factorization.
531042115230331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 32400, while the sum is 34.
Adding to 531042115230331 its reverse (133032511240135), we get a palindrome (664074626470466).
The spelling of 531042115230331 in words is "five hundred thirty-one trillion, forty-two billion, one hundred fifteen million, two hundred thirty thousand, three hundred thirty-one".
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