Base | Representation |
---|---|
bin | 1111011101001001001… |
… | …10110111111101101011 |
3 | 1212202201021101210012021 |
4 | 13232210212313331223 |
5 | 32200033403202111 |
6 | 1043542502325311 |
7 | 53236505614306 |
oct | 7564446677553 |
9 | 1782637353167 |
10 | 531042631531 |
11 | 1952397a2a85 |
12 | 86b05129837 |
13 | 3b1005285b9 |
14 | 1b9b9d15b3d |
15 | dc3105ed71 |
hex | 7ba49b7f6b |
531042631531 has 2 divisors, whose sum is σ = 531042631532. Its totient is φ = 531042631530.
The previous prime is 531042631513. The next prime is 531042631577. The reversal of 531042631531 is 135136240135.
Together with previous prime (531042631513) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 531042631531 - 211 = 531042629483 is a prime.
It is a super-2 number, since 2×5310426315312 (a number of 24 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (531042638531) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265521315765 + 265521315766.
It is an arithmetic number, because the mean of its divisors is an integer number (265521315766).
Almost surely, 2531042631531 is an apocalyptic number.
531042631531 is a deficient number, since it is larger than the sum of its proper divisors (1).
531042631531 is an equidigital number, since it uses as much as digits as its factorization.
531042631531 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 32400, while the sum is 34.
Adding to 531042631531 its reverse (135136240135), we get a palindrome (666178871666).
The spelling of 531042631531 in words is "five hundred thirty-one billion, forty-two million, six hundred thirty-one thousand, five hundred thirty-one".
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