Base | Representation |
---|---|
bin | 110001011101010000… |
… | …111000001011011111 |
3 | 12002001221010121120110 |
4 | 301131100320023133 |
5 | 1332224201004210 |
6 | 40221253421103 |
7 | 3556655133063 |
oct | 613520701337 |
9 | 162057117513 |
10 | 53104313055 |
11 | 20581000432 |
12 | a36063a793 |
13 | 5013c47c61 |
14 | 27dab2baa3 |
15 | 15ac191420 |
hex | c5d4382df |
53104313055 has 32 divisors (see below), whose sum is σ = 89472119040. Its totient is φ = 26821670400.
The previous prime is 53104312999. The next prime is 53104313089. The reversal of 53104313055 is 55031340135.
It is not a de Polignac number, because 53104313055 - 214 = 53104296671 is a prime.
It is a super-3 number, since 3×531043130553 (a number of 33 digits) contains 333 as substring.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 765024 + ... + 831546.
It is an arithmetic number, because the mean of its divisors is an integer number (2796003720).
Almost surely, 253104313055 is an apocalyptic number.
53104313055 is a deficient number, since it is larger than the sum of its proper divisors (36367805985).
53104313055 is a wasteful number, since it uses less digits than its factorization.
53104313055 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 69351.
The product of its (nonzero) digits is 13500, while the sum is 30.
The spelling of 53104313055 in words is "fifty-three billion, one hundred four million, three hundred thirteen thousand, fifty-five".
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