Base | Representation |
---|---|
bin | 110001011101011000… |
… | …100110111001110000 |
3 | 12002002001221120020202 |
4 | 301131120212321300 |
5 | 1332230210330230 |
6 | 40221405054332 |
7 | 3560011302650 |
oct | 613530467160 |
9 | 162061846222 |
10 | 53106339440 |
11 | 20582164930 |
12 | a3612573a8 |
13 | 50144a73bb |
14 | 27db0d8360 |
15 | 15ac441a45 |
hex | c5d626e70 |
53106339440 has 480 divisors, whose sum is σ = 170768784384. Its totient is φ = 14890106880.
The previous prime is 53106339439. The next prime is 53106339467. The reversal of 53106339440 is 4493360135.
53106339440 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a junction number, because it is equal to n+sod(n) for n = 53106339394 and 53106339403.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 40944872 + ... + 40946168.
Almost surely, 253106339440 is an apocalyptic number.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 53106339440, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (85384392192).
53106339440 is an abundant number, since it is smaller than the sum of its proper divisors (117662444944).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
53106339440 is a wasteful number, since it uses less digits than its factorization.
53106339440 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1385 (or 1362 counting only the distinct ones).
The product of its (nonzero) digits is 116640, while the sum is 38.
Adding to 53106339440 its reverse (4493360135), we get a palindrome (57599699575).
The spelling of 53106339440 in words is "fifty-three billion, one hundred six million, three hundred thirty-nine thousand, four hundred forty".
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