Base | Representation |
---|---|
bin | 11000001001101101000110… |
… | …10010011100001110010011 |
3 | 20222001021012220220110011211 |
4 | 30010312203102130032103 |
5 | 23430123300043313233 |
6 | 304542222443520551 |
7 | 14121033363411112 |
oct | 1404664322341623 |
9 | 228037186813154 |
10 | 53110010135443 |
11 | 15a16913167878 |
12 | 5b590aab29157 |
13 | 238333888b181 |
14 | d18776ba1c79 |
15 | 6217a72ee5cd |
hex | 304da349c393 |
53110010135443 has 2 divisors, whose sum is σ = 53110010135444. Its totient is φ = 53110010135442.
The previous prime is 53110010135401. The next prime is 53110010135459. The reversal of 53110010135443 is 34453101001135.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 53110010135443 - 221 = 53110008038291 is a prime.
It is not a weakly prime, because it can be changed into another prime (53110010135473) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26555005067721 + 26555005067722.
It is an arithmetic number, because the mean of its divisors is an integer number (26555005067722).
Almost surely, 253110010135443 is an apocalyptic number.
53110010135443 is a deficient number, since it is larger than the sum of its proper divisors (1).
53110010135443 is an equidigital number, since it uses as much as digits as its factorization.
53110010135443 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 10800, while the sum is 31.
Adding to 53110010135443 its reverse (34453101001135), we get a palindrome (87563111136578).
The spelling of 53110010135443 in words is "fifty-three trillion, one hundred ten billion, ten million, one hundred thirty-five thousand, four hundred forty-three".
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