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53110010135473 is a prime number
BaseRepresentation
bin11000001001101101000110…
…10010011100001110110001
320222001021012220220110012221
430010312203102130032301
523430123300043313343
6304542222443521041
714121033363411154
oct1404664322341661
9228037186813187
1053110010135473
1115a169131678a5
125b590aab29181
13238333888b1a5
14d18776ba1c9b
156217a72ee5ed
hex304da349c3b1

53110010135473 has 2 divisors, whose sum is σ = 53110010135474. Its totient is φ = 53110010135472.

The previous prime is 53110010135461. The next prime is 53110010135489. The reversal of 53110010135473 is 37453101001135.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 39163915739664 + 13946094395809 = 6258108^2 + 3734447^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-53110010135473 is a prime.

It is not a weakly prime, because it can be changed into another prime (53110010135443) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26555005067736 + 26555005067737.

It is an arithmetic number, because the mean of its divisors is an integer number (26555005067737).

Almost surely, 253110010135473 is an apocalyptic number.

It is an amenable number.

53110010135473 is a deficient number, since it is larger than the sum of its proper divisors (1).

53110010135473 is an equidigital number, since it uses as much as digits as its factorization.

53110010135473 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 18900, while the sum is 34.

The spelling of 53110010135473 in words is "fifty-three trillion, one hundred ten billion, ten million, one hundred thirty-five thousand, four hundred seventy-three".