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53110059170197 is a prime number
BaseRepresentation
bin11000001001101101001100…
…01101011111100110010101
320222001021100100011200012211
430010312212031133212111
523430123400121421242
6304542231354513421
714121034530245431
oct1404664615374625
9228037310150184
1053110059170197
1115a16938909367
125b59103435871
132383345a99113
14d1877d4c79c1
156217ab788317
hex304da635f995

53110059170197 has 2 divisors, whose sum is σ = 53110059170198. Its totient is φ = 53110059170196.

The previous prime is 53110059170159. The next prime is 53110059170221. The reversal of 53110059170197 is 79107195001135.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 51807187593841 + 1302871576356 = 7197721^2 + 1141434^2 .

It is a cyclic number.

It is not a de Polignac number, because 53110059170197 - 231 = 53107911686549 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 53110059170197.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (53110059170107) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26555029585098 + 26555029585099.

It is an arithmetic number, because the mean of its divisors is an integer number (26555029585099).

Almost surely, 253110059170197 is an apocalyptic number.

It is an amenable number.

53110059170197 is a deficient number, since it is larger than the sum of its proper divisors (1).

53110059170197 is an equidigital number, since it uses as much as digits as its factorization.

53110059170197 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 297675, while the sum is 49.

The spelling of 53110059170197 in words is "fifty-three trillion, one hundred ten billion, fifty-nine million, one hundred seventy thousand, one hundred ninety-seven".