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5311006365997 is a prime number
BaseRepresentation
bin100110101001001000010…
…1001011101100100101101
3200210201122011110110220101
41031102100221131210231
51144003420112202442
615143502002151101
71055464455153223
oct115222051354455
920721564413811
105311006365997
1117684266aa502
12719385352491
132c6a97238c77
141450a8574b13
15932412cacb7
hex4d490a5d92d

5311006365997 has 2 divisors, whose sum is σ = 5311006365998. Its totient is φ = 5311006365996.

The previous prime is 5311006365971. The next prime is 5311006366019. The reversal of 5311006365997 is 7995636001135.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4554835250436 + 756171115561 = 2134206^2 + 869581^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5311006365997 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5311006365937) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2655503182998 + 2655503182999.

It is an arithmetic number, because the mean of its divisors is an integer number (2655503182999).

Almost surely, 25311006365997 is an apocalyptic number.

It is an amenable number.

5311006365997 is a deficient number, since it is larger than the sum of its proper divisors (1).

5311006365997 is an equidigital number, since it uses as much as digits as its factorization.

5311006365997 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4592700, while the sum is 55.

The spelling of 5311006365997 in words is "five trillion, three hundred eleven billion, six million, three hundred sixty-five thousand, nine hundred ninety-seven".