Base | Representation |
---|---|
bin | 110001011101101010… |
… | …011011001111101011 |
3 | 12002002101201212102221 |
4 | 301131222123033223 |
5 | 1332232404312113 |
6 | 40222053134511 |
7 | 3560066065402 |
oct | 613552331753 |
9 | 162071655387 |
10 | 53111010283 |
11 | 20584865131 |
12 | a36292a437 |
13 | 5015451406 |
14 | 27db992639 |
15 | 15aca6598d |
hex | c5da9b3eb |
53111010283 has 2 divisors, whose sum is σ = 53111010284. Its totient is φ = 53111010282.
The previous prime is 53111010193. The next prime is 53111010313. The reversal of 53111010283 is 38201011135.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 53111010283 - 29 = 53111009771 is a prime.
It is a super-3 number, since 3×531110102833 (a number of 33 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (53111070283) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26555505141 + 26555505142.
It is an arithmetic number, because the mean of its divisors is an integer number (26555505142).
Almost surely, 253111010283 is an apocalyptic number.
53111010283 is a deficient number, since it is larger than the sum of its proper divisors (1).
53111010283 is an equidigital number, since it uses as much as digits as its factorization.
53111010283 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 720, while the sum is 25.
The spelling of 53111010283 in words is "fifty-three billion, one hundred eleven million, ten thousand, two hundred eighty-three".
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