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531125141 is a prime number
BaseRepresentation
bin11111101010000…
…101001110010101
31101000101221201112
4133222011032111
52041432001031
6124411504405
716106326541
oct3752051625
91330357645
10531125141
112528961a8
12129a58105
1386062241
1450778a21
153196562b
hex1fa85395

531125141 has 2 divisors, whose sum is σ = 531125142. Its totient is φ = 531125140.

The previous prime is 531125123. The next prime is 531125197. The reversal of 531125141 is 141521135.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 333610225 + 197514916 = 18265^2 + 14054^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-531125141 is a prime.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (531125341) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265562570 + 265562571.

It is an arithmetic number, because the mean of its divisors is an integer number (265562571).

Almost surely, 2531125141 is an apocalyptic number.

It is an amenable number.

531125141 is a deficient number, since it is larger than the sum of its proper divisors (1).

531125141 is an equidigital number, since it uses as much as digits as its factorization.

531125141 is an evil number, because the sum of its binary digits is even.

The product of its digits is 600, while the sum is 23.

The square root of 531125141 is about 23046.1524120622. The cubic root of 531125141 is about 809.8394952004.

Adding to 531125141 its reverse (141521135), we get a palindrome (672646276).

The spelling of 531125141 in words is "five hundred thirty-one million, one hundred twenty-five thousand, one hundred forty-one".