Base | Representation |
---|---|
bin | 110001011101110000… |
… | …001010110110100111 |
3 | 12002002111120100220111 |
4 | 301131300022312213 |
5 | 1332233301003012 |
6 | 40222145313451 |
7 | 3560114636305 |
oct | 613560126647 |
9 | 162074510814 |
10 | 53112516007 |
11 | 205856a3431 |
12 | a363335887 |
13 | 501585a885 |
14 | 27dbc65275 |
15 | 15acc61ba7 |
hex | c5dc0ada7 |
53112516007 has 2 divisors, whose sum is σ = 53112516008. Its totient is φ = 53112516006.
The previous prime is 53112515987. The next prime is 53112516019. The reversal of 53112516007 is 70061521135.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 53112516007 - 223 = 53104127399 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 53112516007.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53112516707) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26556258003 + 26556258004.
It is an arithmetic number, because the mean of its divisors is an integer number (26556258004).
Almost surely, 253112516007 is an apocalyptic number.
53112516007 is a deficient number, since it is larger than the sum of its proper divisors (1).
53112516007 is an equidigital number, since it uses as much as digits as its factorization.
53112516007 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6300, while the sum is 31.
The spelling of 53112516007 in words is "fifty-three billion, one hundred twelve million, five hundred sixteen thousand, seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •