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53112921133 is a prime number
BaseRepresentation
bin110001011101110001…
…101101110000101101
312002002112022221122011
4301131301231300231
51332233401434013
640222202121221
73560121244366
oct613561556055
9162075287564
1053112921133
112058594a848
12a3634b0211
1350159700ac
1427dbd2cb6d
1515acce1c3d
hexc5dc6dc2d

53112921133 has 2 divisors, whose sum is σ = 53112921134. Its totient is φ = 53112921132.

The previous prime is 53112921107. The next prime is 53112921137. The reversal of 53112921133 is 33112921135.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 43096514409 + 10016406724 = 207597^2 + 100082^2 .

It is a cyclic number.

It is not a de Polignac number, because 53112921133 - 25 = 53112921101 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 53112921095 and 53112921104.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (53112921137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26556460566 + 26556460567.

It is an arithmetic number, because the mean of its divisors is an integer number (26556460567).

Almost surely, 253112921133 is an apocalyptic number.

It is an amenable number.

53112921133 is a deficient number, since it is larger than the sum of its proper divisors (1).

53112921133 is an equidigital number, since it uses as much as digits as its factorization.

53112921133 is an evil number, because the sum of its binary digits is even.

The product of its digits is 4860, while the sum is 31.

The spelling of 53112921133 in words is "fifty-three billion, one hundred twelve million, nine hundred twenty-one thousand, one hundred thirty-three".