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5311330331134 = 247496711375783
BaseRepresentation
bin100110101001010001111…
…1101010010100111111110
3200210202110202001121112011
41031102203331102213332
51144010101031044014
615143554054001434
71055505500625052
oct115224375224776
920722422047464
105311330331134
111768582562293
1271945594627a
132c6b193a7c09
141450d95c5c62
159325e9707c4
hex4d4a3f529fe

5311330331134 has 16 divisors (see below), whose sum is σ = 8138144867328. Its totient is φ = 2598638136952.

The previous prime is 5311330331129. The next prime is 5311330331171. The reversal of 5311330331134 is 4311330331135.

It is a junction number, because it is equal to n+sod(n) for n = 5311330331096 and 5311330331105.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5220994 + ... + 6154789.

It is an arithmetic number, because the mean of its divisors is an integer number (508634054208).

Almost surely, 25311330331134 is an apocalyptic number.

5311330331134 is a deficient number, since it is larger than the sum of its proper divisors (2826814536194).

5311330331134 is a wasteful number, since it uses less digits than its factorization.

5311330331134 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11380799.

The product of its (nonzero) digits is 14580, while the sum is 31.

Adding to 5311330331134 its reverse (4311330331135), we get a palindrome (9622660662269).

Subtracting from 5311330331134 its reverse (4311330331135), we obtain a palindrome (999999999999).

The spelling of 5311330331134 in words is "five trillion, three hundred eleven billion, three hundred thirty million, three hundred thirty-one thousand, one hundred thirty-four".

Divisors: 1 2 47 94 4967 9934 233449 466898 11375783 22751566 534661801 1069323602 56503514161 113007028322 2655665165567 5311330331134