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5311434130 = 25531143413
BaseRepresentation
bin1001111001001011…
…00000110110010010
3111201011101210212121
410330211200312102
541334211343010
62235014244454
7245423305462
oct47445406622
914634353777
105311434130
112286191092
12104295672a
13668530c42
143855adba2
152114733da
hex13c960d92

5311434130 has 8 divisors (see below), whose sum is σ = 9560581452. Its totient is φ = 2124573648.

The previous prime is 5311434119. The next prime is 5311434133. The reversal of 5311434130 is 314341135.

It can be written as a sum of positive squares in 2 ways, for example, as 5306102649 + 5331481 = 72843^2 + 2309^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×53114341302 = 56422665034657713800, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 5311434095 and 5311434104.

It is not an unprimeable number, because it can be changed into a prime (5311434133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 265571697 + ... + 265571716.

Almost surely, 25311434130 is an apocalyptic number.

5311434130 is a deficient number, since it is larger than the sum of its proper divisors (4249147322).

5311434130 is a wasteful number, since it uses less digits than its factorization.

5311434130 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 531143420.

The product of its (nonzero) digits is 2160, while the sum is 25.

The square root of 5311434130 is about 72879.5865109017. The cubic root of 5311434130 is about 1744.7663094307.

Adding to 5311434130 its reverse (314341135), we get a palindrome (5625775265).

The spelling of 5311434130 in words is "five billion, three hundred eleven million, four hundred thirty-four thousand, one hundred thirty".

Divisors: 1 2 5 10 531143413 1062286826 2655717065 5311434130