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53115403121719 is a prime number
BaseRepresentation
bin11000001001110111001001…
…01111000011010000110111
320222001210010202202112120021
430010323210233003100313
523430220321144343334
6304544513534150011
714121314130136141
oct1404734457032067
9228053122675507
1053115403121719
1115a1913038a224
125b5a155052307
1323839b7c73b03
14d18b2911dc91
156219c09d13b4
hex304ee4bc3437

53115403121719 has 2 divisors, whose sum is σ = 53115403121720. Its totient is φ = 53115403121718.

The previous prime is 53115403121579. The next prime is 53115403121747. The reversal of 53115403121719 is 91712130451135.

53115403121719 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 53115403121719 - 219 = 53115402597431 is a prime.

It is a super-2 number, since 2×531154031217192 (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (53115403121749) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26557701560859 + 26557701560860.

It is an arithmetic number, because the mean of its divisors is an integer number (26557701560860).

Almost surely, 253115403121719 is an apocalyptic number.

53115403121719 is a deficient number, since it is larger than the sum of its proper divisors (1).

53115403121719 is an equidigital number, since it uses as much as digits as its factorization.

53115403121719 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 113400, while the sum is 43.

The spelling of 53115403121719 in words is "fifty-three trillion, one hundred fifteen billion, four hundred three million, one hundred twenty-one thousand, seven hundred nineteen".