Base | Representation |
---|---|
bin | 11000001001110111001001… |
… | …10111000011000001001111 |
3 | 20222001210010220201000221112 |
4 | 30010323210313003001033 |
5 | 23430220322213432441 |
6 | 304544514051122235 |
7 | 14121314154016313 |
oct | 1404734467030117 |
9 | 228053126630845 |
10 | 53115405217871 |
11 | 15a19131591087 |
12 | 5b5a1558a337b |
13 | 23839b8528c39 |
14 | d18b29507b43 |
15 | 6219c0c974eb |
hex | 304ee4dc304f |
53115405217871 has 2 divisors, whose sum is σ = 53115405217872. Its totient is φ = 53115405217870.
The previous prime is 53115405217841. The next prime is 53115405217879. The reversal of 53115405217871 is 17871250451135.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-53115405217871 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53115405217879) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26557702608935 + 26557702608936.
It is an arithmetic number, because the mean of its divisors is an integer number (26557702608936).
Almost surely, 253115405217871 is an apocalyptic number.
53115405217871 is a deficient number, since it is larger than the sum of its proper divisors (1).
53115405217871 is an equidigital number, since it uses as much as digits as its factorization.
53115405217871 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1176000, while the sum is 50.
The spelling of 53115405217871 in words is "fifty-three trillion, one hundred fifteen billion, four hundred five million, two hundred seventeen thousand, eight hundred seventy-one".
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