Base | Representation |
---|---|
bin | 11000001001110111001001… |
… | …11111000011010000100001 |
3 | 20222001210011001122122001001 |
4 | 30010323210333003100201 |
5 | 23430220323233103001 |
6 | 304544514204112001 |
7 | 14121314210605312 |
oct | 1404734477032041 |
9 | 228053131578031 |
10 | 53115407316001 |
11 | 15a19132794478 |
12 | 5b5a156535601 |
13 | 23839b8ab1c34 |
14 | d18b298d2609 |
15 | 6219c105e001 |
hex | 304ee4fc3421 |
53115407316001 has 2 divisors, whose sum is σ = 53115407316002. Its totient is φ = 53115407316000.
The previous prime is 53115407315989. The next prime is 53115407316067. The reversal of 53115407316001 is 10061370451135.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 27168863565376 + 25946543750625 = 5212376^2 + 5093775^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-53115407316001 is a prime.
It is not a weakly prime, because it can be changed into another prime (53115407316901) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26557703658000 + 26557703658001.
It is an arithmetic number, because the mean of its divisors is an integer number (26557703658001).
Almost surely, 253115407316001 is an apocalyptic number.
It is an amenable number.
53115407316001 is a deficient number, since it is larger than the sum of its proper divisors (1).
53115407316001 is an equidigital number, since it uses as much as digits as its factorization.
53115407316001 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 37800, while the sum is 37.
Adding to 53115407316001 its reverse (10061370451135), we get a palindrome (63176777767136).
The spelling of 53115407316001 in words is "fifty-three trillion, one hundred fifteen billion, four hundred seven million, three hundred sixteen thousand, one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •