Base | Representation |
---|---|
bin | 11000001001110111001001… |
… | …11111000011010000010101 |
3 | 20222001210011001122122000121 |
4 | 30010323210333003100111 |
5 | 23430220323233102424 |
6 | 304544514204111541 |
7 | 14121314210605264 |
oct | 1404734477032025 |
9 | 228053131578017 |
10 | 53115407315989 |
11 | 15a19132794467 |
12 | 5b5a1565355b1 |
13 | 23839b8ab1c25 |
14 | d18b298d25db |
15 | 6219c105dee4 |
hex | 304ee4fc3415 |
53115407315989 has 2 divisors, whose sum is σ = 53115407315990. Its totient is φ = 53115407315988.
The previous prime is 53115407315947. The next prime is 53115407316001. The reversal of 53115407315989 is 98951370451135.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 50841819819025 + 2273587496964 = 7130345^2 + 1507842^2 .
It is a cyclic number.
It is not a de Polignac number, because 53115407315989 - 215 = 53115407283221 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53115407310989) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26557703657994 + 26557703657995.
It is an arithmetic number, because the mean of its divisors is an integer number (26557703657995).
Almost surely, 253115407315989 is an apocalyptic number.
It is an amenable number.
53115407315989 is a deficient number, since it is larger than the sum of its proper divisors (1).
53115407315989 is an equidigital number, since it uses as much as digits as its factorization.
53115407315989 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 20412000, while the sum is 61.
The spelling of 53115407315989 in words is "fifty-three trillion, one hundred fifteen billion, four hundred seven million, three hundred fifteen thousand, nine hundred eighty-nine".
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