Base | Representation |
---|---|
bin | 110001011110000010… |
… | …010010110111000001 |
3 | 12002002211111202120202 |
4 | 301132002102313001 |
5 | 1332241010024033 |
6 | 40222435214545 |
7 | 3560203215611 |
oct | 613602226701 |
9 | 162084452522 |
10 | 53117267393 |
11 | 205883491a3 |
12 | a364a47455 |
13 | 5016832448 |
14 | 27dc740a41 |
15 | 15ad39e8e8 |
hex | c5e092dc1 |
53117267393 has 2 divisors, whose sum is σ = 53117267394. Its totient is φ = 53117267392.
The previous prime is 53117267383. The next prime is 53117267443. The reversal of 53117267393 is 39376271135.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 46767090049 + 6350177344 = 216257^2 + 79688^2 .
It is a cyclic number.
It is not a de Polignac number, because 53117267393 - 232 = 48822300097 is a prime.
It is a super-3 number, since 3×531172673933 (a number of 33 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (53117267383) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26558633696 + 26558633697.
It is an arithmetic number, because the mean of its divisors is an integer number (26558633697).
Almost surely, 253117267393 is an apocalyptic number.
It is an amenable number.
53117267393 is a deficient number, since it is larger than the sum of its proper divisors (1).
53117267393 is an equidigital number, since it uses as much as digits as its factorization.
53117267393 is an evil number, because the sum of its binary digits is even.
The product of its digits is 714420, while the sum is 47.
The spelling of 53117267393 in words is "fifty-three billion, one hundred seventeen million, two hundred sixty-seven thousand, three hundred ninety-three".
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