Search a number
-
+
5311730433120 = 25351732397931
BaseRepresentation
bin100110101001011101111…
…0011100011110001100000
3200210210111121220220021020
41031102323303203301200
51144011410442324440
615144101505325440
71055521426503126
oct115227363436140
920723447826236
105311730433120
111768768397891
12719547936880
132c6b81253a57
141451367b5916
1593284b543d0
hex4d4bbce3c60

5311730433120 has 384 divisors, whose sum is σ = 18550608491520. Its totient is φ = 1275164549120.

The previous prime is 5311730433083. The next prime is 5311730433211. The reversal of 5311730433120 is 213340371135.

It is a happy number.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 54190555 + ... + 54288485.

It is an arithmetic number, because the mean of its divisors is an integer number (48308876280).

Almost surely, 25311730433120 is an apocalyptic number.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 5311730433120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (9275304245760).

5311730433120 is an abundant number, since it is smaller than the sum of its proper divisors (13238878058400).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

5311730433120 is a wasteful number, since it uses less digits than its factorization.

5311730433120 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 98023 (or 97981 counting only the distinct ones).

The product of its (nonzero) digits is 22680, while the sum is 33.

The spelling of 5311730433120 in words is "five trillion, three hundred eleven billion, seven hundred thirty million, four hundred thirty-three thousand, one hundred twenty".