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53121454234999 is a prime number
BaseRepresentation
bin11000001010000010011010…
…11010001101110101110111
320222002100202110222221110221
430011001031122031311313
523430320214241004444
6304551354214355211
714121620104556623
oct1405011532156567
9228070673887427
1053121454234999
1115a20756051197
125b5b36365bb07
1323844407c7907
14d19140a36183
15621c26d63a84
hex30504d68dd77

53121454234999 has 2 divisors, whose sum is σ = 53121454235000. Its totient is φ = 53121454234998.

The previous prime is 53121454234873. The next prime is 53121454235039. The reversal of 53121454234999 is 99943245412135.

53121454234999 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 53121454234999 - 215 = 53121454202231 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (53121454234699) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26560727117499 + 26560727117500.

It is an arithmetic number, because the mean of its divisors is an integer number (26560727117500).

Almost surely, 253121454234999 is an apocalyptic number.

53121454234999 is a deficient number, since it is larger than the sum of its proper divisors (1).

53121454234999 is an equidigital number, since it uses as much as digits as its factorization.

53121454234999 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 41990400, while the sum is 61.

The spelling of 53121454234999 in words is "fifty-three trillion, one hundred twenty-one billion, four hundred fifty-four million, two hundred thirty-four thousand, nine hundred ninety-nine".