Base | Representation |
---|---|
bin | 11111101010011… |
… | …011000111111001 |
3 | 1101000120111202202 |
4 | 133222123013321 |
5 | 2041442333331 |
6 | 124413435545 |
7 | 16110152213 |
oct | 3752330771 |
9 | 1330514682 |
10 | 531214841 |
11 | 252947633 |
12 | 129a9bbb5 |
13 | 86094011 |
14 | 5079d5b3 |
15 | 31981ecb |
hex | 1fa9b1f9 |
531214841 has 2 divisors, whose sum is σ = 531214842. Its totient is φ = 531214840.
The previous prime is 531214807. The next prime is 531214843. The reversal of 531214841 is 148412135.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 346146025 + 185068816 = 18605^2 + 13604^2 .
It is a cyclic number.
It is not a de Polignac number, because 531214841 - 210 = 531213817 is a prime.
Together with 531214843, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (531214843) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265607420 + 265607421.
It is an arithmetic number, because the mean of its divisors is an integer number (265607421).
Almost surely, 2531214841 is an apocalyptic number.
It is an amenable number.
531214841 is a deficient number, since it is larger than the sum of its proper divisors (1).
531214841 is an equidigital number, since it uses as much as digits as its factorization.
531214841 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 3840, while the sum is 29.
The square root of 531214841 is about 23048.0984248159. The cubic root of 531214841 is about 809.8850830215.
Adding to 531214841 its reverse (148412135), we get a palindrome (679626976).
The spelling of 531214841 in words is "five hundred thirty-one million, two hundred fourteen thousand, eight hundred forty-one".
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