Base | Representation |
---|---|
bin | 110001011110010100… |
… | …110001111111011001 |
3 | 12002010011121222012002 |
4 | 301132110301333121 |
5 | 1332243230112442 |
6 | 40223131130345 |
7 | 3560262341315 |
oct | 613624617731 |
9 | 162104558162 |
10 | 53122113497 |
11 | 20590059142 |
12 | a3665a39b5 |
13 | 501783b16b |
14 | 27dd242b45 |
15 | 15ada0a732 |
hex | c5e531fd9 |
53122113497 has 2 divisors, whose sum is σ = 53122113498. Its totient is φ = 53122113496.
The previous prime is 53122113479. The next prime is 53122113521. The reversal of 53122113497 is 79431122135.
Together with previous prime (53122113479) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 27796892176 + 25325221321 = 166724^2 + 159139^2 .
It is a cyclic number.
It is not a de Polignac number, because 53122113497 - 212 = 53122109401 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 53122113497.
It is not a weakly prime, because it can be changed into another prime (53122113437) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26561056748 + 26561056749.
It is an arithmetic number, because the mean of its divisors is an integer number (26561056749).
Almost surely, 253122113497 is an apocalyptic number.
It is an amenable number.
53122113497 is a deficient number, since it is larger than the sum of its proper divisors (1).
53122113497 is an equidigital number, since it uses as much as digits as its factorization.
53122113497 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 45360, while the sum is 38.
The spelling of 53122113497 in words is "fifty-three billion, one hundred twenty-two million, one hundred thirteen thousand, four hundred ninety-seven".
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