Base | Representation |
---|---|
bin | 11000001010000100001111… |
… | …10101101011100010010101 |
3 | 20222002110021210120020011020 |
4 | 30011002013311223202111 |
5 | 23430324221213404140 |
6 | 304552035353231353 |
7 | 14121653310030252 |
oct | 1405020765534225 |
9 | 228073253506136 |
10 | 53122434513045 |
11 | 15a21109424637 |
12 | 5b5b597a02559 |
13 | 238456891b0b1 |
14 | d191d4ccc429 |
15 | 621c82e4b6d0 |
hex | 305087d6b895 |
53122434513045 has 32 divisors (see below), whose sum is σ = 85951441395072. Its totient is φ = 28015214314752.
The previous prime is 53122434512971. The next prime is 53122434513059. The reversal of 53122434513045 is 54031543422135.
It is not a de Polignac number, because 53122434513045 - 29 = 53122434512533 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 53122434512988 and 53122434513006.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 54662922 + ... + 55626251.
It is an arithmetic number, because the mean of its divisors is an integer number (2685982543596).
Almost surely, 253122434513045 is an apocalyptic number.
It is an amenable number.
53122434513045 is a deficient number, since it is larger than the sum of its proper divisors (32829006882027).
53122434513045 is a wasteful number, since it uses less digits than its factorization.
53122434513045 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 110289541.
The product of its (nonzero) digits is 864000, while the sum is 42.
The spelling of 53122434513045 in words is "fifty-three trillion, one hundred twenty-two billion, four hundred thirty-four million, five hundred thirteen thousand, forty-five".
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