Search a number
-
+
53123140100 = 2252531231401
BaseRepresentation
bin110001011110011000…
…101100101000000100
312002010020120010102102
4301132120230220010
51332244010440400
640223205131232
73560304145322
oct613630545004
9162106503372
1053123140100
112059069a478
12a3669b9b18
135017b0a514
1427dd42cd12
1515adb5e9d5
hexc5e62ca04

53123140100 has 18 divisors (see below), whose sum is σ = 115277214234. Its totient is φ = 21249256000.

The previous prime is 53123140097. The next prime is 53123140121. The reversal of 53123140100 is 104132135.

It can be written as a sum of positive squares in 3 ways, for example, as 178970884 + 52944169216 = 13378^2 + 230096^2 .

It is a Harshad number since it is a multiple of its sum of digits (20).

It is an unprimeable number.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 265615601 + ... + 265615800.

Almost surely, 253123140100 is an apocalyptic number.

53123140100 is a gapful number since it is divisible by the number (50) formed by its first and last digit.

It is an amenable number.

53123140100 is an abundant number, since it is smaller than the sum of its proper divisors (62154074134).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

53123140100 is a wasteful number, since it uses less digits than its factorization.

53123140100 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 531231415 (or 531231408 counting only the distinct ones).

The product of its (nonzero) digits is 360, while the sum is 20.

Adding to 53123140100 its reverse (104132135), we get a palindrome (53227272235).

The spelling of 53123140100 in words is "fifty-three billion, one hundred twenty-three million, one hundred forty thousand, one hundred".

Divisors: 1 2 4 5 10 20 25 50 100 531231401 1062462802 2124925604 2656157005 5312314010 10624628020 13280785025 26561570050 53123140100